0=-16x^2+324

Solution for 0=-16x^2+324 equation:

0=-16x^2+324

We move all terms to the left:

0-(-16x^2+324)=0

We add all the numbers together, and all the variables

-(-16x^2+324)=0

We get rid of parentheses

16x^2-324=0

a = 16; b = 0; c = -324;
Δ = b2-4ac
Δ = 02-4·16·(-324)
Δ = 20736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{20736}=144$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-144}{2*16}=\frac{-144}{32}
=-4+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+144}{2*16}=\frac{144}{32}
=4+1/2
$